Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The viscous force acting on a body falling under gravity in a viscous fluid will be Option: 1 <img alt="\frac{6\pi \vartheta }{\eta r}" src="/la

The viscous force acting on a body falling under gravity in a viscous fluid will be 

Option: 1

\frac{6\pi \vartheta }{\eta r}

 

 

 


Option: 2

\frac{6\pi \eta r }{\vartheta }


Option: 3

6\pi \eta r\vartheta


Option: 4

\frac{r\vartheta }{6\pi \eta }


Answers (1)

best_answer

As we learned 

 

Stoke's law -

The magnitude of the viscous force depends on shape/size ,velocity and viscosity of liquid.

- wherein

 

 Viscous force F= 6\pi \eta rv

\eta =coefficient\: of\: viscosity

r=radius\: of\: body

v=velocity\: of\: spherical\: body

 

 

Posted by

manish

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG: Delhi HC seeks NTA's response on plea alleging defective biometric system at centre
anam-khan

‘NTA is national corruption agency; conduct high-level probe or dissolve': NSUI after CBI FIR, arrests in NEET
anam-khan

'Munna Bhai' again: CBI books two medical students for fraud in NEET-UG 2023

Latest Question