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Two bodies of mass 4kg and 6kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:  
Option: 1 g
Option: 2 \frac{g}{2}
Option: 3 \frac{g}{5}
Option: 4 \frac{g}{10}

Answers (1)

best_answer

For block of 4 kg and 6 kg -

So,

For 4 kg block - 

T - 4g = 4a . ..............(1)

And for 6 kg block -

6g - T = 6a  .................. (2)

By adding (1) and (2)

a= \frac{g}{5}

Posted by

Deependra Verma

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