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Two gases of A and B having molar masses 60g and 45g respectively are enclosed in a vessel. The mass of A is 0.50g and that of B is 0.20g. The total pressure of the mixture is 750mm. Calculate the partial pressure of A and B gases respectively.

Option: 1

345.8mm, 260.7mm


Option: 2

589.2mm, 342.7mm


Option: 3

236.5mm, 432.5mm


Option: 4

487.5mm, 262.5mm


Answers (1)

best_answer

We have:
Molar mass of A = 60g and molar mass of B = 45g
Given mass of A = 0.50g and given mass of B = 0.20g
Now, the total pressure of the mixture

P_{mixture} = 750mm

Now, moles of A = 0.50/60 = 0.0084 moles
And, moles of B = 0.20/45 = 0.0045 moles
Again, mole fraction of A = 0.0084/0.0129 = 0.65
And, mole fraction of B = 0.0045/0.0129 = 0.35
Thus, partial pressure of A (P_{A} ) = 750 x 0.65                                                                        = 487.5mm
Again, partial pressure of B(P_{B} ) = 262.5mm
Therefore, Option(4) is correct

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Nehul

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