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  • Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3. Given that <img alt="\mathrm{\Lambda^{o}_

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3. Given that \mathrm{\Lambda^{o}_{\text{Al}^{3+}}} and \mathrm{\Lambda^{o}_{\text{SO}^{2-}_{4}}} are the equivalent conductances at infinite dilution of the respective ions?

Option: 1

\mathrm{2\Lambda^{o}_{\text{Al}^{3+}}+3\Lambda^{o}_{\text{SO}^{2-}_{4}}}


Option: 2

\mathrm{\Lambda^{o}_{\text{Al}^{3+}}+\Lambda^{o}_{\text{SO}^{2-}_{4}}}


Option: 3

\mathrm{\left (\Lambda^{o}_{\text{Al}^{3+}}+\Lambda^{o}_{\text{SO}^{2-}_{4}} \right )\times 6}


Option: 4

\mathrm{\frac{1}{3}\Lambda^{o}_{\text{Al}^{3+}}+\frac{1}{2}\Lambda^{o}_{\text{SO}^{2-}_{4}}}


Answers (1)

best_answer

We know,

\mathrm{A l_{2}(SO_{4})_{3} \rightleftharpoons 2 A l^{3+}+3 S O_{4}^{2-}}

The equivalent conductivity of any electrolyte at infinite dilution, \mathrm{\Lambda_{e q}^{o}}  is the sum of ionic conductances of the cation and anion given by the electrolytes at infinite dilution

\mathrm{\Lambda_{e q}^{o}=\Lambda_{A l^{3+}}^{o}+\Lambda_{S O_{4}^{2-}}^{o}}

So, Option 2 is correct.

Posted by

Anam Khan

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