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Which of the following statements is true about the bond length of peroxide and superoxide ions?

 

Option: 1

The bond length of the peroxide ion is larger because it has a lower bond order.
 


Option: 2

The bond length of the superoxide ion is larger because it has a lower bond order.
 


Option: 3

The bond length of the peroxide ion is smaller because it has a lower bond order.
 


Option: 4

The bond length of the superoxide ion is smaller because it has a lower bond order.


Answers (1)

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The bond length in a molecule is dependent on bond order. The higher is the bond order, the smaller will be the bond length.

Peroxide ion, \mathrm{O}_2^{2-}

\mathrm{\begin{aligned} & \mathrm{O}_2^{2-}: \quad \mathrm{KK}^*(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_z\right)^2 \\ & \left(\pi 2 p_x\right)^2\left(\pi 2 p_y\right)^2\left(\pi^* 2 p_x\right)^2\left(\pi^* 2 p_y\right)^2 \end{aligned}}

\mathrm{\text { Bond order }=\frac{10-8}{2}=1}

Superoxide ion,  \mathrm{O}_2^{-}

\mathrm{\begin{aligned} & \mathrm{O}_2^{-}: \mathrm{KK}^*(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_z\right)^2\left(\pi 2 p_x\right)^2 \\ & \left(\pi 2 p_y\right)^2\left(\pi^* 2 p_x\right)^2\left(\pi^* 2 p_y\right)^1 \end{aligned}}

Bond order =\frac{10-7}{2}=1.5

Bond order of superoxide ion is higher than peroxide ion, hence bond length of peroxide ion is larger.

Posted by

Divya Prakash Singh

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