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  • Which product is most favourable ? <img alt="\mathrm{Rb^{+}+\left(Cl B r I^{-}\right) \stackrel{\Delta}{\longrightarrow}}" src="/latex-image/?%5Cmathrm%7BRb%5E%7B&plus;%7D&plus;%5

Which product is most favourable ?

\mathrm{Rb^{+}+\left(Cl B r I^{-}\right) \stackrel{\Delta}{\longrightarrow}}

Option: 1

\mathrm{RbI}+\mathrm{BrCl}


Option: 2

\mathrm{RbBr}+\mathrm{ICl}


Option: 3

\mathrm{\mathrm{RbCl}+IBr}


Option: 4

None of the above 


Answers (1)

best_answer

It is because \text{RbCl} has greater lattice energy , so it can be easily formed.For the lattice energy to be high, the anion should be small in size. The size of anion is in the order

\mathrm{Cl}^{-}<\mathrm{Br}<\mathrm{I}^{-}

Posted by

vishal kumar

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