Get Answers to all your Questions

header-bg qa

XeF2 is isostructural with:

Option: 1

BaCl2


Option: 2

TeF2


Option: 3

\text{ICl}_{2}^{-}


Option: 4

SbCI3


Answers (1)

best_answer

To find hybridization,

SN = \frac{V+M-Q}{2}

Where, 

V is the number of valence electron central atom

M is the number of surrounding atoms except for O 

Q is charge present(if any)

SN is the steric number which is equal to the total number of bond pair and lone pair of electrons.

For XeF2 

SN =\frac{8+2}{2}=5 

 

Hence,sp3d hybridization, 2 bond pair and 3 lone pair. 

For ICl_{2}^{-}

SN=\frac{7+2+1}{2}=5

Hence, hybridization is sp3d, 2 bond pair and 3 lone pair.

Therefore, Option(3) is correct.

Posted by

Sayak

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks