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NCERT Solutions for Class 12 Physics Chapter 13 Nuclei serve as a crucial resource for achieving high scores in both board exams and competitive ones like JEE and NEET. On this NCERT solution page, you'll discover comprehensive and detailed class 12 nuclei ncert solutions to the entire exercise, ranging from questions 13.1 to 13.22 (exercise questions) and 13.23 to 13.31 (additional exercise questions). Additionally, these class 12 physics chapter 13 exercise solutions are conveniently available in PDF format, allowing students to access them offline, free from any internet constraints.
Do you know that the size of an atom is 10,000 times the size of a nucleus? But the nucleus contains 99.9% of the mass of an atom. We know that an atom has a structure. Does the nucleus also have a structure? If so what are the constituents and how they are arranged? All these questions are answered in Nuclei Class 12 NCERT text book.
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Nuclei Class 12 chapter comes under modern Physics and you can expect at least one question for the board exam from NCERT Class 12 Physics chapter 13. Learning the class 12 physics chapter nuclei ncert solutions is important to score well in the board exam. The questions in NCERT Solutions for Class 12 Physics Chapter 13 Nuclei are divided into two parts namely exercise and additional exercise. Nuclei Class 12 NCERT solutions download PDF option is available to read the solution offline.
Free download physics chapter 13 class 12 ncert solutions pdf for CBSE exam.
NCERT solutions for class 12 physics chapter 13 nuclei: Exercise Solution
Answer:
Mass of the two stable isotopes and their respective abundances are and and and .
m=6.940934 u
Answer:
The atomic mass of boron is 10.811 u
Mass of the two stable isotopes are and respectively
Let the two isotopes have abundances x% and (100-x)%
Therefore the abundance of is 19.89% and that of is 80.11%
Answer:
The atomic masses of the three isotopes are 19.99 u(m 1 ), 20.99 u(m 2 ) and 21.99u(m 3 )
Their respective abundances are 90.51%(p 1 ), 0.27%(p 2 ) and 9.22%(p 3 )
The average atomic mass of neon is 20.1771 u.
Q. 13.3 Obtain the binding energy( in MeV ) of a nitrogen nucleus , given m
Answer:
m n = 1.00866 u
m p = 1.00727 u
Atomic mass of Nitrogen m= 14.00307 u
Mass defect m=7 m n +7 m p - m
m=7 1.00866+7 1.00727 - 14.00307
m=0.10844
Now 1u is equivalent to 931.5 MeV
E b =0.10844 931.5
E b =101.01186 MeV
Therefore binding energy of a Nitrogen nucleus is 101.01186 MeV.
Q. 13.4 (i) Obtain the binding energy of the nuclei and in units of MeV from the following data:
Answer:
m H = 1.007825 u
m n = 1.008665 u
The atomic mass of is m=55.934939 u
Mass defect
m=0.528461
Now 1u is equivalent to 931.5 MeV
E b =0.528461 931.5
E b =492.2614215 MeV
Therefore the binding energy of a nucleus is 492.2614215 MeV.
Average binding energy
Q. 13.4 (ii) Obtain the binding energy of the nuclei and in units of MeV from the following data:
Answer:
m H = 1.007825 u
m n = 1.008665 u
The atomic mass of is m=208.980388 u
Mass defect
m=126 1.008665+83 1.007825 - 208.980388
m=1.760877 u
Now 1u is equivalent to 931.5 MeV
E b =1.760877 931.5
E b =1640.2569255 MeV
Therefore the binding energy of a nucleus is 1640.2569255 MeV.
Answer:
Mass of the coin is w = 3g
Total number of Cu atoms in the coin is n
n=2.871 10 22
m H = 1.007825 u
m n = 1.008665 u
Atomic mass of is m=62.92960 u
Mass defect m=(63-29) m n +29 m H - m
m=34 1.008665+29 1.007825 - 62.92960
m=0.591935 u
Now 1u is equivalent to 931.5 MeV
E b =0.591935 931.5
E b =551.38745 MeV
Therefore binding energy of a nucleus is 551.38745 MeV.
The nuclear energy that would be required to separate all the neutrons and protons from each other is
n E b =2.871 10 22 551.38745
=1.5832 10 25 MeV
=1.5832 10 25 1.6 10 -19 10 6 J
=2.5331 10 9 kJ
Q.13.6 (i) Write nuclear reaction equations for
Answer:
The nuclear reaction equations for the given alpha decay
Q.13.6 (ii) Write nuclear reaction equations for
Answer:
The nuclear reaction equations for the given alpha decay is
Q.13.6 (iii) Write nuclear reaction equations for
Answer:
The nuclear reaction equations for the given beta minus decay is
Q.13.6 (iv) Write nuclear reaction equations for
Answer:
The nuclear reaction equation for the given beta minus decay is
Q.13.6 (v) Write nuclear reaction equations for
Answer:
The nuclear reaction for the given beta plus decay will be
Q.13.6 (vii) Write nuclear reaction equations for
Electron capture of
Answer:
The nuclear reaction for electron capture of is
Answer:
(a) The activity is proportional to the number of radioactive isotopes present
The number of half years in which the number of radioactive isotopes reduces to x% of its original value is n.
In this case
It will take 5T years to reach 3.125% of the original activity.
(b) In this case
It will take 6.64T years to reach 1% of the original activity.
Answer:
Since we know that activity is proportional to the number of radioactive isotopes present in the sample.
Also
but
Therefore
The age of the Indus-Valley civilisation calculated using the given specimen is approximately 4217 years.
Answer:
Required activity=8.0 mCi
1 Ci=3.7 10 10 decay s -1
8.0 mCi=8 10 -3 3.7 10 10 =2.96 10 8 decay s -1
T 1/2 =5.3 years
Mass of those many atoms of Cu will be
7.12 10 -6 g of is necessary to provide a radioactive source of 8.0 mCi strength.
Q. 13.10 The half-life of is 28 years. What is the disintegration rate of 15 mg of this isotope?
Answer:
T 1/2 =28 years
The number of atoms in 15 mg of is
N=1.0038 10 20
The disintegration rate will be
=-1.0038 10 20 7.85 10 -10
=-7.88 10 10 s -1
The disintegration rate is therefore 7.88 10 10 decay s -1 .
Q.13.11 Obtain approximately the ratio of the nuclear radii of the gold isotope and the silver isotope
Answer:
The nuclear radii are directly proportional to the cube root of the mass number.
The ratio of the radii of the given isotopes is therefore
Q.13.12 Find the Q-value and the kinetic energy of the emitted -particle in the -decay of
Answer:
Mass defect is m
m=226.02540-222.0175-4.002603
m=0.005297 u
1 u = 931.5 MeV/c 2
Q-value= m 931.5
=4.934515 MeV
By using Linear Momentum Conservation and Energy Conservation
The kinetic energy of alpha particle =
=
=4.847 MeV
Q.13.12 (b) Find the Q-value and the kinetic energy of the emitted -particle in the -decay of
Answer:
Mass defect is m
m=220.01137-216.00189-4.002603
m=0.006877 u
1 u = 931.5 MeV/c 2
Q-value= m 931.5
=6.406 MeV
By using Linear Momentum Conservation and Energy Conservation
The kinetic energy of alpha particle =
=
=6.289 MeV
Q.13.13 The radionuclide decays according to
The maximum energy of the emitted positron is .
and
calculate Q and compare it with the maximum energy of the positron emitted.
Answer:
If we use atomic masses
Q-value= 0.001033 931.5=0.9622 MeV which is comparable with a maximum energy of the emitted positron.
Answer:
The decay equation is
(we did not subtract the mass of the electron as it is cancelled because of the presence of one more electron in the sodium atom)
Q=0.004696 931.5
Q=4.3743 eV
The emitted nucleus is way heavier than the particle and the energy of the antineutrino is also negligible and therefore the maximum energy of the emitted electron is equal to the Q value.
the following
Atomic masses are given to be
Answer:
The above negative value of mass defect implies there will be a negative Q value and therefore the reaction is endothermic
Atomic masses are given to be
Answer:
The above positive value of mass defect implies Q value would be positive and therefore the reaction is exothermic
Answer:
The reaction will be
The mass defect of the reaction will be
Since the mass defect is negative the Q value will also negative and therefore the fission is not energetically possible
Answer:
Number of atoms present in 1 kg(w) of =n
Energy per fission (E)=180 MeV
Total Energy released if all the atoms in 1 kg undergo fission = E n
=180 2.52 10 24
=4.536 10 26 MeV
Answer:
The amount of energy liberated on fission of 1 atom is 200 MeV.
The amount of energy liberated on fission of 1g
Total Energy produced in the reactor in 5 years
Mass of which underwent fission, m
=1537.8 kg
The amount present initially in the reactor = 2m
=2 1537.8
=3075.6 kg
Answer:
The energy liberated on the fusion of two atoms of deuterium= 3.27 MeV
Number of fusion reactions in 2 kg of deuterium = N A 500
The energy liberated by fusion of 2.0 kg of deuterium atoms E
Power of lamp (P)= 100 W
Time the lamp would glow using E amount of energy is T=
=4.99 10 4 years
Answer:
For a head-on collision of two deuterons, the closest distances between their centres will be d=2 r
d=2 2.0
d=4.0 fm
d=4 10 -15 m
charge on each deuteron = charge of one proton=q =1.6 10 -19 C
The maximum electrostatic potential energy of the system during the head-on collision will be E
The above basically means to bring two deuterons from infinity to each other would require 360 keV of work to be done or would require 360 keV of energy to be spent.
Answer:
Mass of an element with mass number A will be about A u. The density of its nucleus, therefore, would be
As we can see the above density comes out to be independent of mass number A and R 0 is constant, so matter density is nearly constant
Show that if emission is energetically allowed, electron capture is necessarily allowed but not vice–versa.
Answer:
For the electron capture, the reaction would be
The mass defect and q value of the above reaction would be
where m N and m N are the nuclear masses of elements X and Y respectively
For positron emission, the reaction would be
The mass defect and q value for the above reaction would be
From the above values, we can see that if Q 2 is positive Q 1 will also be positive but Q 1 being positive does not imply that Q 2 will also have to positive.
Answer:
Let the abundances of and be x and y respectively.
x+y+78.99=100
y=21.01-x
The average atomic mass of Mg is 24.312 u
The abundances of and are 9.3% and 11.71% respectively
Answer:
The reaction showing the neutron separation is
But 1u=931.5 MeV/c 2
Therefore E=(0.008978) 931.5
E=8.363007 MeV
Therefore to remove a neutron from the nucleus 8.363007 MeV of energy is required
Answer:
The reaction showing the neutron separation is
But 1u=931.5 MeV/c 2
Therefore E=(0.014019) 931.5
E=13.059 MeV
Therefore to remove a neutron from the nucleus 13.059 MeV of energy is required
Answer:
Let initially there be N 1 atoms of and N 2 atoms of and let their decay constants be and respectively
Since initially the activity of is 1/9 times that of we have
(i)
Let after time t the activity of be 9 times that of
(ii)
Dividing equation (ii) by (i) and taking the natural log of both sides we get
where and
t comes out to be 208.5 days
Q.13.26 Under certain circumstances, a nucleus can decay by emitting a particle more massive than an -particle. Consider the following decay processes:
Calculate the Q-values for these decays and determine that both are energetically allowed.
Answer:
1 u = 931.5 MeV/c 2
Q=0.03419 931.5
=31.848 MeV
As the Q value is positive the reaction is energetically allowed
1 u = 931.5 MeV/c 2
Q=0.00642 931.5
=5.98 MeV
As the Q value is positive the reaction is energetically allowed
Answer:
The fission reaction given in the question can be written as
The mass defect for the above reaction would be
In the above equation, m N represents nuclear masses
but 1u =931.5 MeV/c 2
Q=0.247995 931.5
Q=231.007 MeV
Q value of the fission process is 231.007 MeV
Q.13.28 (i) Consider the D–T reaction (deuterium-tritium fusion)
(a) Calculate the energy released in MeV in this reaction from the data:
Answer:
The mass defect of the reaction is
1u = 931.5 MeV/c 2
Q=0.018883 931.5=17.59 MeV
Q.13.28 (b) Consider the D–T reaction (deuterium–tritium fusion)
(b) Consider the radius of both deuterium and tritium to be approximately 2.0 fm. What is the kinetic energy needed to overcome the coulomb repulsion between the two nuclei? To what temperature must the gas be heated to initiate the reaction? (Hint: Kinetic energy required for one fusion event =average thermal kinetic energy available with the interacting particles ; k = Boltzman’s constant, T = absolute temperature.)
Answer:
To initiate the reaction both the nuclei would have to come in contact with each other.
Just before the reaction the distance between their centres would be 4.0 fm.
The electrostatic potential energy of the system at that point would be
The same amount of Kinetic Energy K would be required to overcome the electrostatic forces of repulsion to initiate the reaction
It is given that
Therefore the temperature required to initiate the reaction is
Answer:
decays from 1.088 MeV to 0 V
Frequency of is
Plank's constant, h=6.62 10 -34 Js
Similarly, we can calculate frequencies of and
The energy of the highest level would be equal to the energy released after the decay
Mass defect is
We know 1u = 931.5 MeV/c 2
Q value= 0.001473 931.5=1.3721 MeV
The maximum Kinetic energy of would be 1.3721-1.088=0.2841 MeV
The maximum Kinetic energy of would be 1.3721-0.412=0.9601 MeV
Answer:
(a)
The above fusion reaction releases the energy of 26 MeV
Number of Hydrogen atoms in 1.0 kg of Hydrogen is 1000N A
Therefore 250N A such reactions would take place
The energy released in the whole process is E 1
(b) The energy released in fission of one atom is 200 MeV
Number of atoms present in 1 kg of is N
The energy released on fission of N atoms is E 2
Answer:
Let the amount of energy to be produced using nuclear power per year in 2020 is E
(Only 10% of the required electrical energy is to be produced by Nuclear power and only 25% of therm-nuclear is successfully converted into electrical energy)
Amount of Uranium required to produce this much energy is M
(N A =6.023 10 23 , Atomic mass of Uranium is 235 g)
=3.076 10 4 kg
This chapter revolves around the topic of 'Nuclei,' and class 12 physics chapter 13 exercise solutions are vital for several reasons. Firstly, understanding nuclear physics is crucial as it forms the basis for numerous advanced concepts. Secondly, scoring in this chapter can be relatively easier compared to some other physics chapters, provided one grasps the fundamentals. The exercise solutions provide a comprehensive breakdown of each question, aiding students in mastering this essential topic effectively and efficiently, even within a limited time frame.
The following formulas will be helpful to understand the NCERT solutions for Class 12 Physics chapter 13 Nuclei
As per latest 2024 syllabus. Physics formulas, equations, & laws of class 11 & 12th chapters
Where A is the mass number and
Here Z is the atomic number, M is the mass of the nucleus and A is the mass number. This equation tells that the mass of the nucleus is always less than the mass of their constituents.
Where c is the speed of light.
Where N is the number of nuclei at any time t, is the number of nuclei at any time and lambda is disintegration constant.
Where lambda is the disintegration constant.
After completing all these topics try to do NCERT class 12 chapter 13 exercises. If you are unable to solve or have any doubts refer to the solutions of NCERT class 12 physics chapter 13 nuclei provided below.
Comprehensive Coverage: These class 12 nuclei ncert solutions encompass all topics and questions found in Chapter 13, ensuring a thorough understanding of nuclear physics.
Detailed Explanations: Each nuclei class 12 ncert solutions offers comprehensive, step-by-step explanations, making complex nuclear physics concepts accessible to students.
Clarity and Simplicity: The class 12 physics chapter nuclei ncert solutions are presented in clear and straightforward language, ensuring ease of understanding.
Practice Questions: Exercise questions are included for practice and self-assessment, enhancing students' problem-solving skills.
Exam Preparation: These physics chapter 13 class 12 ncert solutions are essential for board exam preparation and provide valuable support for competitive exams.
Foundation for Advanced Study: The concepts explored in this chapter serve as the foundation for more advanced studies in nuclear physics and related fields.
Free Access: These solutions are available for free, ensuring accessibility to all students
NCERT Exemplar Class 12 Solutions
For CBSE board exam from NCERT class, 12 chapters 13 around 4 to 6 marks questions can be expected. All topics of the NCERT syllabus for the chapter Nuclei should be covered for the CBSE board exam.
Yes the NCERT chapter Nuclei are important for both the exams. Both in NEET and JEE main syllabus the chapter Nuclei is present and 1 or 2 questions from the chapter can be expected for the exams. The questions discussed in the NCERT Solutions for the chapter Nuclei will give a better idea on how to use the formulas and give a better understanding of the concepts discussed.
The nucleus is made up of protons, which are positively charged particles, and neutrons, which are neutral particles.
Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons in their nuclei.
nuclei ncert solutions are important for the Board exam as they provide clear explanations, help in solving questions, cover all important topics, provide a structured approach to solving problems, and are designed with the exam pattern in mind, helping in exam-oriented preparation.
hello,
Yes you can appear for the compartment paper again since CBSE gives three chances to a candidate to clear his/her exams so you still have two more attempts. However, you can appear for your improvement paper for all subjects but you cannot appear for the ones in which you have failed.
I hope this was helpful!
Good Luck
Hello dear,
If you was not able to clear 1st compartment and now you giving second compartment so YES, you can go for your improvement exam next year but if a student receives an improvement, they are given the opportunity to retake the boards as a private candidate the following year, but there are some requirements. First, the student must pass all of their subjects; if they received a compartment in any subject, they must then pass the compartment exam before being eligible for the improvement.
As you can registered yourself as private candidate for giving your improvement exam of 12 standard CBSE(Central Board of Secondary Education).For that you have to wait for a whole year which is bit difficult for you.
Positive side of waiting for whole year is you have a whole year to preparing yourself for your examination. You have no distraction or something which may causes your failure in the exams. In whole year you have to stay focused on your 12 standard examination for doing well in it. By this you get a highest marks as a comparison of others.
Believe in Yourself! You can make anything happen
All the very best.
Hello Student,
I appreciate your Interest in education. See the improvement is not restricted to one subject or multiple subjects and we cannot say if improvement in one subject in one year leads to improvement in more subjects in coming year.
You just need to have a revision of all subjects what you have completed in the school. have a revision and practice of subjects and concepts helps you better.
All the best.
If you'll do hard work then by hard work of 6 months you can achieve your goal but you have to start studying for it dont waste your time its a very important year so please dont waste it otherwise you'll regret.
Yes, you can take admission in class 12th privately there are many colleges in which you can give 12th privately.
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The audiologist career involves audiology professionals who are responsible to treat hearing loss and proactively preventing the relevant damage. Individuals who opt for a career as an audiologist use various testing strategies with the aim to determine if someone has a normal sensitivity to sounds or not. After the identification of hearing loss, a hearing doctor is required to determine which sections of the hearing are affected, to what extent they are affected, and where the wound causing the hearing loss is found. As soon as the hearing loss is identified, the patients are provided with recommendations for interventions and rehabilitation such as hearing aids, cochlear implants, and appropriate medical referrals. While audiology is a branch of science that studies and researches hearing, balance, and related disorders.
The hospital Administrator is in charge of organising and supervising the daily operations of medical services and facilities. This organising includes managing of organisation’s staff and its members in service, budgets, service reports, departmental reporting and taking reminders of patient care and services.
For an individual who opts for a career as an actor, the primary responsibility is to completely speak to the character he or she is playing and to persuade the crowd that the character is genuine by connecting with them and bringing them into the story. This applies to significant roles and littler parts, as all roles join to make an effective creation. Here in this article, we will discuss how to become an actor in India, actor exams, actor salary in India, and actor jobs.
Individuals who opt for a career as acrobats create and direct original routines for themselves, in addition to developing interpretations of existing routines. The work of circus acrobats can be seen in a variety of performance settings, including circus, reality shows, sports events like the Olympics, movies and commercials. Individuals who opt for a career as acrobats must be prepared to face rejections and intermittent periods of work. The creativity of acrobats may extend to other aspects of the performance. For example, acrobats in the circus may work with gym trainers, celebrities or collaborate with other professionals to enhance such performance elements as costume and or maybe at the teaching end of the career.
Career as a video game designer is filled with excitement as well as responsibilities. A video game designer is someone who is involved in the process of creating a game from day one. He or she is responsible for fulfilling duties like designing the character of the game, the several levels involved, plot, art and similar other elements. Individuals who opt for a career as a video game designer may also write the codes for the game using different programming languages.
Depending on the video game designer job description and experience they may also have to lead a team and do the early testing of the game in order to suggest changes and find loopholes.
Radio Jockey is an exciting, promising career and a great challenge for music lovers. If you are really interested in a career as radio jockey, then it is very important for an RJ to have an automatic, fun, and friendly personality. If you want to get a job done in this field, a strong command of the language and a good voice are always good things. Apart from this, in order to be a good radio jockey, you will also listen to good radio jockeys so that you can understand their style and later make your own by practicing.
A career as radio jockey has a lot to offer to deserving candidates. If you want to know more about a career as radio jockey, and how to become a radio jockey then continue reading the article.
The word “choreography" actually comes from Greek words that mean “dance writing." Individuals who opt for a career as a choreographer create and direct original dances, in addition to developing interpretations of existing dances. A Choreographer dances and utilises his or her creativity in other aspects of dance performance. For example, he or she may work with the music director to select music or collaborate with other famous choreographers to enhance such performance elements as lighting, costume and set design.
A multimedia specialist is a media professional who creates, audio, videos, graphic image files, computer animations for multimedia applications. He or she is responsible for planning, producing, and maintaining websites and applications.
A career as social media manager involves implementing the company’s or brand’s marketing plan across all social media channels. Social media managers help in building or improving a brand’s or a company’s website traffic, build brand awareness, create and implement marketing and brand strategy. Social media managers are key to important social communication as well.
In a career as a copywriter, one has to consult with the client and understand the brief well. A career as a copywriter has a lot to offer to deserving candidates. Several new mediums of advertising are opening therefore making it a lucrative career choice. Students can pursue various copywriter courses such as Journalism, Advertising, Marketing Management. Here, we have discussed how to become a freelance copywriter, copywriter career path, how to become a copywriter in India, and copywriting career outlook.
Careers in journalism are filled with excitement as well as responsibilities. One cannot afford to miss out on the details. As it is the small details that provide insights into a story. Depending on those insights a journalist goes about writing a news article. A journalism career can be stressful at times but if you are someone who is passionate about it then it is the right choice for you. If you want to know more about the media field and journalist career then continue reading this article.
For publishing books, newspapers, magazines and digital material, editorial and commercial strategies are set by publishers. Individuals in publishing career paths make choices about the markets their businesses will reach and the type of content that their audience will be served. Individuals in book publisher careers collaborate with editorial staff, designers, authors, and freelance contributors who develop and manage the creation of content.
In a career as a vlogger, one generally works for himself or herself. However, once an individual has gained viewership there are several brands and companies that approach them for paid collaboration. It is one of those fields where an individual can earn well while following his or her passion.
Ever since internet costs got reduced the viewership for these types of content has increased on a large scale. Therefore, a career as a vlogger has a lot to offer. If you want to know more about the Vlogger eligibility, roles and responsibilities then continue reading the article.
Individuals in the editor career path is an unsung hero of the news industry who polishes the language of the news stories provided by stringers, reporters, copywriters and content writers and also news agencies. Individuals who opt for a career as an editor make it more persuasive, concise and clear for readers. In this article, we will discuss the details of the editor's career path such as how to become an editor in India, editor salary in India and editor skills and qualities.
Linguistic meaning is related to language or Linguistics which is the study of languages. A career as a linguistic meaning, a profession that is based on the scientific study of language, and it's a very broad field with many specialities. Famous linguists work in academia, researching and teaching different areas of language, such as phonetics (sounds), syntax (word order) and semantics (meaning).
Other researchers focus on specialities like computational linguistics, which seeks to better match human and computer language capacities, or applied linguistics, which is concerned with improving language education. Still, others work as language experts for the government, advertising companies, dictionary publishers and various other private enterprises. Some might work from home as freelance linguists. Philologist, phonologist, and dialectician are some of Linguist synonym. Linguists can study French, German, Italian.
The career of a travel journalist is full of passion, excitement and responsibility. Journalism as a career could be challenging at times, but if you're someone who has been genuinely enthusiastic about all this, then it is the best decision for you. Travel journalism jobs are all about insightful, artfully written, informative narratives designed to cover the travel industry. Travel Journalist is someone who explores, gathers and presents information as a news article.
Welding Engineer Job Description: A Welding Engineer work involves managing welding projects and supervising welding teams. He or she is responsible for reviewing welding procedures, processes and documentation. A career as Welding Engineer involves conducting failure analyses and causes on welding issues.
A quality controller plays a crucial role in an organisation. He or she is responsible for performing quality checks on manufactured products. He or she identifies the defects in a product and rejects the product.
A quality controller records detailed information about products with defects and sends it to the supervisor or plant manager to take necessary actions to improve the production process.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
A QA Lead is in charge of the QA Team. The role of QA Lead comes with the responsibility of assessing services and products in order to determine that he or she meets the quality standards. He or she develops, implements and manages test plans.
A metallurgical engineer is a professional who studies and produces materials that bring power to our world. He or she extracts metals from ores and rocks and transforms them into alloys, high-purity metals and other materials used in developing infrastructure, transportation and healthcare equipment.
An Azure Administrator is a professional responsible for implementing, monitoring, and maintaining Azure Solutions. He or she manages cloud infrastructure service instances and various cloud servers as well as sets up public and private cloud systems.
An AWS Solution Architect is someone who specializes in developing and implementing cloud computing systems. He or she has a good understanding of the various aspects of cloud computing and can confidently deploy and manage their systems. He or she troubleshoots the issues and evaluates the risk from the third party.
Careers in computer programming primarily refer to the systematic act of writing code and moreover include wider computer science areas. The word 'programmer' or 'coder' has entered into practice with the growing number of newly self-taught tech enthusiasts. Computer programming careers involve the use of designs created by software developers and engineers and transforming them into commands that can be implemented by computers. These commands result in regular usage of social media sites, word-processing applications and browsers.
A Product Manager is a professional responsible for product planning and marketing. He or she manages the product throughout the Product Life Cycle, gathering and prioritising the product. A product manager job description includes defining the product vision and working closely with team members of other departments to deliver winning products.
Individuals in the information security manager career path involves in overseeing and controlling all aspects of computer security. The IT security manager job description includes planning and carrying out security measures to protect the business data and information from corruption, theft, unauthorised access, and deliberate attack
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