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Q2. 1500 families with 2 children were selected randomly, and the following data were

Compute the probability of a family, chosen at random, having

(iii) No girl

Answers (1)

From the above question, the data that we can take is,

Total Number of families= 475+814+211 = 1500

Number of families having no girls in the family =211

We know:

Empirical (or experimental) probability P(E) of this event can be written as

P(Family, chosen at random has no girls) =

 \frac{Families\:with\:no\:girl}{Total Number of families}

= 211/1500

Ans:= 211/1500

Posted by

Amit Singh

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