Q 7.15 (b)  100\mu F capacitor in series with a 40\Omega resistance is connected to a 110\; V,  60\: Hz  supply. What is the time lag between the current maximum and the voltage maximum?

Answers (1)

In the case of a capacitor, we have 

tan\phi=\frac{\frac{1}{wC}}{R}=\frac{1}{wCR}

So,

tan\phi=\frac{1}{wCR}=\frac{1}{2\pi 60 *100*10^{-6}*40}=0.6635

\phi=33.56^0

So the time lag between max voltage and the max current is :

t=\frac{\phi }{w}=\frac{33.56\pi}{180*2\pi*60}=1.55ms

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