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# A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

3. A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of  the ladder from the wall.

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Here. As we can see, The ladder with wall forms a right-angled triangle with

the vertical height of the wall = perpendicular = 12 m

length of ladder = Hypotenuse = 15 m

Now, As we know

In a Right-angled Triangle: By Pythagoras Theorem,

$(Hypotenus)^2=(Base)^2+(Perpendicular)^2$

$(15)^2=(Base)^2+(12)^2$

$(Base)^2=(15)^2-(12)^2$

$(Base)^2=225-144$

$(Base)^2=81$

$Base=9 m$

Hence the distance of the foot of the ladder from the wall is 9 m.

Here. As we can see, The ladder with wall forms a right-angled triangle with

the vertical height of the wall = perpendicular = 12 m

length of ladder = Hypotenuse = 15 m

Now, As we know

In a Right-angled Triangle: By Pythagoras Theorem,

$(Hypotenus)^2=(Base)^2+(Perpendicular)^2$

$(15)^2=(Base)^2+(12)^2$

$(Base)^2=(15)^2-(12)^2$

$(Base)^2=225-144$

$(Base)^2=81$

$Base=9 m$

Hence the distance of the foot of the ladder from the wall is 9 m.

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