Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. A 600 p F capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 p F capacitor. How much electrostatic energy is lost in the process?

Filters

Select Stream
Select Type
Select Exam
Select Subject
Select Chapter
Q&A - Ask Doubts and Get Answers
Q
NCERT

A 600 p F capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 p F capacitor. How much electrostatic energy is lost in the process?

2.11 A 600pF capacitor is charged by a 200V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?

Answers (1)
Views
P Pankaj Sanodiya

Given 

C=600pF

V=200V

Energy stored :

E=\frac{1}{2}CV^2=\frac{1}{2}*600*10^{-12}*200*200=1.2*10^{-5}J

Now, when it is disconnected and connected from another capacitor of capacitance 600pF

New Capacitance 

C'=\frac{600*600}{600+600}=300pF

New electrostatic energy

E'=\frac{1}{2}C'V^2=\frac{1}{2}*300*10^{-12}*200^2=0.6*10^{-5}J

Hence Loss in energy

E-E'=1.2*10^{-5}-0.6*10^{-5}J=0.6*10^{-5}

 

 

Similar Questions

Related Chapters

Exams
Articles
Questions