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A bar magnet of magnetic moment 1.5 J T–1 lies aligned with the direction of a uniform magnetic field of 0.22 T. What is the torque on the(a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment

5.7 (b) A bar magnet of magnetic moment 1.5 JT^{-1} lies aligned with the
direction of a uniform magnetic field of 0.22 T. What is the torque on the magnet in cases (i) and (ii)?

Answers (1)
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For case (i): 

\theta = \theta_2 = 90°

We know, Torque, \tau = MBsin\theta
= (1.5)(0.22)sin90^{\circ}
= 0.33 J

Forcase (ii): 

\theta = \theta_2 = 180°

We know, Torque,

\tau = MBsin\theta
= (1.5)(0.22)sin180^{\circ}
= 0

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