Q. A bus started its journey and reached different places with a speed of 60 km/hour.
 (i) Find the total distance covered by the bus from A to D.
(ii) Find the total distance covered by the bus from D to G.
(iii) Find the total distance covered by the bus, if it starts from A and returns back to A.
(iv) Can you find the difference of distances from C to D and D to E? 
                                                                                     
     

Answers (1)

(i) Total distance from A to D = AB + BC + CD

= (4170 + 3410 + 2160)\ km = 9740\ km

(ii) Total distance between D to G = DE + EF + FG

 = (8140 + 4830 + 2550)\ km = 15520\ km

(iii) Required distance = AD + DG + GA

= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290)\ km = 26550 km

(iv) The difference of distances from C to D and D to E = (8140 - 2160)\ km = 5980\ km

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