Q : 5    A hemispherical bowl made of brass has inner diameter \small 10.5\hspace{1mm}cm. Find the cost of tin-plating it on the inside at the rate of  Rs 16 per \small 100\hspace{1mm}cm^2

Answers (1)

Given,

The inner radius of the hemispherical bowl = r = \frac{10.5}{2}\ cm

We know,

The curved surface area of a hemisphere = 2\pi r^2

\therefore The surface area of the hemispherical bowl = 2\times\frac{22}{7}\times\left (\frac{10.5}{2} \right )^2

=11\times1.5\times10.5

= 173.25 \ cm^2

Now,

Cost of tin-plating \small 100\hspace{1mm}cm^2 =  Rs 16

\therefore Cost of tin-plating \small 33\hspace{1mm}cm^2 =  \small \\ Rs. \left (\frac{16}{100}\times173.25 \right )

\small = Rs. 27.72

Therefore, the cost of tin-plating it on the inside is \small Rs. 27.72

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions