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A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Q : 7    A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
 

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Given, a right circular cone cap (which means no base)

Base radius of the cone = r=7\ cm

Height = h = 24\ cm

\therefore l = \sqrt{h^2+r^2}

We know, Curved surface area of a right circular cone = \pi r l

\therefore The curved surface area of a cap =

\\ = \frac{22}{7}\times7\times\sqrt{24^2+7^2} \\ \\ = 22\times\sqrt{625} \\ = 22\times25\ \\ = 550\ cm^2

\therefore The curved surface area of 10 caps = 550\times10 = 5500\ cm^2

Therefore, the area of the sheet required for 10 caps = 5500\ cm^2

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