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A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm (see Fig. 13.11). Find its (i) inner curved surface area,

Q : 3    A metal pipe is \small 77\hspace{1mm}cm long. The inner diameter of a cross section is \small 4\hspace{1mm}cm, the outer diameter being \small 4.4\hspace{1mm}cm (see Fig.  \small 13.11). Find its

           (i) inner curved surface area,

            

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N Nehul

Note: There are two surfaces, inner and outer.

Given,

Height of the cylinder, h = 77\ cm

Outer diameter  = r_1 = 4.4\ cm

Inner diameter  = r_2 = 4\ cm

 Inner curved surface area = 2\pi r_2h

\\ = 2\times\frac{22}{7}\times2\times77 \\ = 968\ cm^2

Therefore, the inner curved surface area of the cylindrical pipe is 968\ cm^2

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