2.(a) A parallel plate capacitor (Fig. 8.7) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s ^{-1}.

What is the rms value of the conduction current?

Answers (1)

Capacitance(C) of the parallel plate capacitor = 100 pF

Voltage(V) = 230 V

Angular Frequency (ω) = 300\ rad\ s^{-1}

 Rms\ Current(I) =\frac{Voltage}{Capacitive\ Reactance}

 Capacitive \ Reactance(X_{c})= \frac{1}{C\omega }=\frac{1}{100\ pF\times 300\ rad\ s^{-1}}

X_{c}= 3.33\times 10^{7} \Omega

I=\frac{V}{X_{c}}=\frac{230V}{3.33\times 10^{7}\Omega }= 6.9\times 10^{-6}A

RMS value of conduction current is 6.9\mu A 

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