# Q 1.19: A point charge of $2.0\mu C$is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?

Given,

q = net charge inside the cube = $2.0\mu C$

Using Gauss’s law, we know that the flux of electric field through any closed surface S is $1/\epsilon _{0}$  times the total charge enclosed by S.

i.e.   $\phi = q/\epsilon _{0}$

where, q = net charge enclosed  and  $\epsilon _{0}$ = permittivity of free space (constant)

$\therefore \phi = 2.0\times10^{-6}/8.85\times10^{-12}\ Nm^2C^{-1} = \boldsymbol{2.2\times10^5\ Nm^2C^{-1}}$

(Note: Using Gauss's formula, we see that the electric flux through the cube is independent of the position of the charge and dimension of the cube! )

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