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A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant

4.6    A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is  reduced to half ?

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M manish

Let assume the concentration of reactant be x

So, rate of reaction, R = k[x]^{2}

Now, if the concentration of reactant is doubled then x\rightarrow \frac{x}{2} . So the rate of reaction would  be  R = k[\frac{x}{2}]^{2} = \frac{kx^{2}}{4}=\frac{R}{4}

Hence we can say that the rate of reaction reduced to 1/4 times.

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