# 4. A rectangular sheet of paper is  $12\tfrac{1}{2}$  cm long and  $10\tfrac{2}{3}$  cm wide. Find its perimeter.

Given,

Length of the rectangle :

$l=12\tfrac{1}{2}cm=\frac{12\times 2+1}{2}=\frac{25}{2}cm$

Width of the rectangle :

$b=10\tfrac{2}{3}cm=\frac{10\times 3+2}{3}=\frac{32}{3}cm$

Now, As we know,

Perimeter of the rectangle = 2 x ( length + width )

So,

The perimeter of the given rectangle :

$=2\times(l+b)$

$=2\times\left ( \frac{25}{2}+\frac{32}{3} \right )$

Now let's make the denominator of both fractions equal.

$=2\times\left ( \frac{25}{2}\times\frac{3}{3}+\frac{32}{3}\times\frac{2}{2} \right )$

$=2\times\left ( \frac{75}{6}+\frac{64}{6} \right )$

$=2\times\left ( \frac{139}{6} \right )$

$=\frac{139}{3}cm$

Hence, the perimeter of the rectangle is $\frac{139}{3}cm$.

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