4. A rectangular sheet of paper is  12\tfrac{1}{2}  cm long and  10\tfrac{2}{3}  cm wide. Find its perimeter.

        



 

Answers (1)

Given,

Length of the rectangle :

l=12\tfrac{1}{2}cm=\frac{12\times 2+1}{2}=\frac{25}{2}cm

Width of the rectangle :

b=10\tfrac{2}{3}cm=\frac{10\times 3+2}{3}=\frac{32}{3}cm

Now, As we know,

Perimeter of the rectangle = 2 x ( length + width ) 

So,

The perimeter of the given rectangle :

=2\times(l+b)

=2\times\left ( \frac{25}{2}+\frac{32}{3} \right )

Now let's make the denominator of both fractions equal.

=2\times\left ( \frac{25}{2}\times\frac{3}{3}+\frac{32}{3}\times\frac{2}{2} \right )

=2\times\left ( \frac{75}{6}+\frac{64}{6} \right )

=2\times\left ( \frac{139}{6} \right )

=\frac{139}{3}cm

Hence, the perimeter of the rectangle is \frac{139}{3}cm.

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