Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A short bar magnet has a magnetic moment of 0.48 J T -1. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on the axis

5.12 (a). A short bar magnet has a magnetic moment of  0.48 JT^{-1}. Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on the axis,

Answers (1)

best_answer

Given,

The magnetic moment of the bar magnet, m = 0.48 JT^{-1}

Distance from the centre, d = 10 cm = 0.1 m

We know, The magnetic field at distance d, from the centre of the magnet on the axis is:

B= \frac{\mu_{0} m}{2\pi r^3}

\therefore B= \frac{4\pi\times10^{-7}\times 0.48}{2\pi (0.1)^3}

\implies B = 0.96 \times 10^{-4} T

Therefore, the magnetic field on the axis, B = 0.96 G

Note: The magnetic field is along the S−N direction (like a dipole!).

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE admit card 2025 out for Class 10, 12 supplementary exams
anam-khan

CBSE Class 10, 12 practical exams 2025 for compartment students from July 10; detailed guidelines issued
anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in

Latest Question