Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 into 10 minus 2 J. What is the magnitude of magnetic moment of the magnet?

5.3. A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 \times 10 ^{-2} J . What is the magnitude of the magnetic moment of the magnet?

Answers (1)

best_answer

Given,

The angle between axis of a bar magnet and the external magnetic field, θ = 30°

Magnetic field strength, B = 0.25 T

Torque on the bar magnet, Τ = 4.5 x 10^{-2}J

We know,

Torque experienced by a bar magnet placed in a uniform magnetic field is:

T = m x B = mBsin\theta

m = \frac{T}{Bsin\theta}

\implies m = \frac{4.5\times10^{-2}J}{0.25T\times sin30^{\circ}}

\therefore  m = 0.36 JT^{-1}

Hence, the magnitude of the moment of the Bar magnet is 0.36 JT^{-1}.

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Central Sector Scheme of Scholarship 2025 applications open on scholarships.gov.in
anam-khan

CBSE Board 2025: Class 10th, 12th supplementary date sheet out; exams from July 15
anam-khan

CBSE issues final reminder to schools for supplementary exam LOC submission; submit by today without late fee

Latest Question