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2.4) A spherical conductor of radius 12 cm has a charge of $1.6\times 10^{-7}C$ distributed uniformly on its surface. What is the electric field (c) at a point 18 cm from the centre of the sphere?

Answers (1)

P Pankaj Sanodiya

Given,

Charge on the conductor $q=1.6*10^{-7}C$

The radius of the spherical conductor $R=12cm=0.12m$

NOW,

the electric field at point 18cm away from the centre of the spherical conductor is given by:

$E=\frac{kq}{r^2}=\frac{1}{4\pi \epsilon }\frac{q}{r^2}=\frac{9*10^9*1.6*10^{-7}}{0.18^2}=4.4*10^4NC^{-1}$

Hence electric field at the point 18cm away from the centre of the sphere is $4.4*10^4NC^{-1}$

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