2.4) A spherical conductor of radius 12 cm has a charge of 1.6 \times 10^{-7}C distributed uniformly on its surface. What is the electric field(b) just outside the sphere

Answers (1)

Given,

Charge on the conductor q=1.6*10^{-7}C

The radius of a spherical conductor R=12cm=0.12m

NOW,

the electric field outside the spherical conductor is given by:

E=\frac{kq}{r^2}=\frac{1}{4\pi \epsilon }\frac{q}{r^2}=\frac{9*10^9*1.6*10^{-7}}{0.12^2}=10^5NC^{-1}

Hence electric field just outside is 10^5NC^{-1}.

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