Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A system has two charges q_A = 2.5 × 10^–7 C and q_B = –2.5 × 10^–7 C located at points A: (0, 0, –15 cm) and B: (0,0, +15 cm) respectively. What are the total charge and electric dipole moment of the system?

Q 1.9: A system has two charges q_{A}=2.5\times 10^{-7}Cand q_{B}=-2.5\times 10^{-7} C located at points A: (0, 0, –15 cm) and B: (0,0, +15 cm), respectively. What is the total charge and electric dipole moment of the system?

Answers (1)

best_answer

Given, 

q_{A}=2.5\times 10^{-7}C and    q_{B}=-2.5\times 10^{-7}

The total charge of the system = q_{A} + q_{B} = 0

\therefore The system is electrically neutral. (All dipole systems have net charge zero!)

Now, distance between the two charges, d = 15 + 15 = 30 cm = 0.3 m

We know that the electric dipole moment of the system, p = q_{A} x d = q_{B} x d (i.e, magnitude of charge x distance between the two charges)

\therefore p = 2.5\times10^{-7} C \times 0.3 m = 7.5\times10^{-8} Cm

The direction of a dipole is towards the positive charge. Hence, in a positive-z direction.

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Single Girl Child Scholarship 2024: Registration extended till January 10; eligibility criteria, amount
anam-khan

CBSE wants international boards reined in; letter to education ministry seeks directions for AIU
anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14

Latest Question