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3.4 (a) Three resistors 2 Ω, 4 Ω and 5 Ω are combined in parallel. What is the total resistance of the combination?

Answers (1)

H HARSH KANKARIA

We know that when resistances are in parallel combination, the total resistance R is given by:

$\frac{1}{R} = \sum \frac{1}{R_{i}}$

Therefore, Total resistance of the given three resistances in parallel combination is

$\frac{1}{R} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}$

$\implies \frac{1}{R} = \frac{1}{2}+\frac{1}{4}+\frac{1}{5} = \frac{10+5+4}{20}=\frac{19}{20}$

$\implies R= \frac{20}{19} = 1.05 \Omega$

Hence, the total resistance is 1.05 $\Omega$

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