17.(b) A toroid has a core (non-ferromagnetic) of inner radius 25 cm and outer radius 26 cm, around which 3500 turns of a wire are wound. If the current in the wire is 11 A, what is the magnetic field inside the core of the toroid?

Answers (1)

The magnetic field inside the core of a toroid is given by

 B=\frac{\mu _{o}NI}{l}

Total number of turns(N)=3500

Current flowing in toroid =11 A

Length of the toroid, l=

\\l=2\pi \left (\frac{ r_{1}+r_{2}}{2} \right )\\ \\l=\pi ( r_{1}+r_{2})\\ \\l=\pi (0.25+0.26)\\ \\l=0.51\pi (r1=inner radius=25 cm, r2=outer radius=26 cm)

B=\frac{4\pi \times 10^{-7}\times 3500\times 11}{0.51\pi }=0.031 T

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