Q

# A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah.

Q. 4.     A verandah of width $2.25\; m$  is constructed all along outside a room which is $5.5\; m$ long and $4\; m$ wide. Find:

(i) the area of the verandah.

Views
R

It is given that room  is $5.5\; m$ long and $4\; m$ wide.

It is clear that it is rectangular shaped with  $length = 5.5 \ m \ and \ breadth = 4 \ m$

We know that the area of the rectangle is $= length \times breadth$

$\Rightarrow length \times breadth = 5.5 \times 4 = 22 \ m^2$                   -(i)

Now, when verandah of width $2.25\; m$  is constructed all along outside the room then length and breadth of the room  is

Area of the room after verandah of width $2.25\; m$  is constructed

$\Rightarrow length \times breadth = 10 \times 8.5 = 85 \ m^2$                              -(ii)

Area of verandah is (ii) - (i)

$\Rightarrow 85-22 = 63 \ m^2$

Therefore, the area of the verandah is  $63 \ m^2$

Exams
Articles
Questions