Q. 4.      A verandah of width 2.25\; m is constructed all along outside a room which is 5.5\; m long and 4\; m wide. Find:

             (ii) the cost of cementing the floor of the verandah at the rate of Rs.200 \; per\; m^{2}.

Answers (1)
R Riya

It is given that room  is 5.5\; m long and 4\; m wide.

It is clear that it is rectangular shaped with  length = 5.5 \ m \ and \ breadth = 4 \ m

We know that the area of the rectangle is = length \times breadth

\Rightarrow length \times breadth = 5.5 \times 4 = 22 \ m^2                   -(i)

Now, when verandah of width 2.25\; m  is constructed all along outside the room then length and breadth of the room  is


Area of the room after verandah of width 2.25\; m  is constructed

\Rightarrow length \times breadth = 10 \times 8.5 = 85 \ m^2                              -(ii)

Area of verandah is (ii) - (i)

\Rightarrow 85-22 = 63 \ m^2

Therefore,  area of verandah is  63 \ m^2

Now, the cost of cementing the floor of the verandah at the rate of Rs.200 \; per\; m^{2} is 

\Rightarrow 63 \times 200 = 12600 \ Rs

Therefore,  cost of cementing the floor of the verandah at the rate of Rs.200 \; per\; m^{2} is Rs \ 12600

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