Q. 4.      A verandah of width $2.25\; m$ is constructed all along outside a room which is $5.5\; m$ long and $4\; m$ wide. Find:             (ii) the cost of cementing the floor of the verandah at the rate of $Rs.200 \; per\; m^{2}$.

R Riya

It is given that room  is $5.5\; m$ long and $4\; m$ wide.

It is clear that it is rectangular shaped with  $length = 5.5 \ m \ and \ breadth = 4 \ m$

We know that the area of the rectangle is $= length \times breadth$

$\Rightarrow length \times breadth = 5.5 \times 4 = 22 \ m^2$                   -(i)

Now, when verandah of width $2.25\; m$  is constructed all along outside the room then length and breadth of the room  is

Area of the room after verandah of width $2.25\; m$  is constructed

$\Rightarrow length \times breadth = 10 \times 8.5 = 85 \ m^2$                              -(ii)

Area of verandah is (ii) - (i)

$\Rightarrow 85-22 = 63 \ m^2$

Therefore,  area of verandah is  $63 \ m^2$

Now, the cost of cementing the floor of the verandah at the rate of $Rs.200 \; per\; m^{2}$ is

$\Rightarrow 63 \times 200 = 12600 \ Rs$

Therefore,  cost of cementing the floor of the verandah at the rate of $Rs.200 \; per\; m^{2}$ is $Rs \ 12600$

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