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  • A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (ii) the cost of cementing the floor

Q. 4. A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
(ii) the cost of cementing the floor of the verandah at the rate of $R s. 200 \mathrm{per} \mathrm{m}^2$.

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It is given that room is 5.5 m long and 4 m wide.
It is clear that it is rectangular shaped with length $=5.5 \mathrm{~m}$ and breadth $=4 \mathrm{~m}$
We know that the area of the rectangle is $=$ length $\times$ breadth
$\Rightarrow$ length $\times$ breadth $=5.5 \times 4=22 \mathrm{~m}^2$--------(i)
Now, when verandah of width $2.25$ m  is constructed all along outside the room then length and breadth of the room  is

Area of the room after verandah of width $2.25$ m is constructed
$\Rightarrow \text { length } \times \text { breadth }=10 \times 8.5=85 \mathrm{~m}^2$------(ii)
Area of verandah is (ii) - (i)
$\Rightarrow 85-22=63 m^2$
Therefore, area of verandah is $63 \mathrm{~m}^2$
Now, the cost of cementing the floor of the verandah at the rate of $R s. 200 \mathrm{per} \mathrm{m}^2$ is

$\Rightarrow 63 \times 200=12600 R s$
Therefore, cost of cementing the floor of the verandah at the rate of Rs. 200 per $\mathrm{m}^2$ is $R \mathrm{~s} 12600$

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Riya

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