Q: 11 ABC and ADC are two right triangles with common hypotenuse AC. Prove that
Given: ABC and ADC are two right triangles with common hypotenuse AC.
To prove :
Triangle ABC and ADC are on common base BC and BAC = BDC.
Thus, point A,B,C,D lie in the same circle.
(If a line segment joining two points subtends equal angles at two other points lying on the same side of line containing line segment, four points lie on the circle.)
CAD = CBD (Angles in same segment are equal)
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