1.  ABC is a triangle. Locate a point in the interior of \small \Delta ABC which is equidistant from all the vertices of \small \Delta ABC.

Answers (1)

We know that circumcenter of a triangle is equidistant from all the vertices. Also, circumcenter is the point of intersection of the perpendicular bisectors of the sides of a triangle.

Thus, draw perpendicular bisectors of each side of the triangle ABC. And let them meet at a point, say O. 

Hence O is the required point which is equidistant from all the vertices.

 

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