2. ABC is a triangle, right-angled at C. If $\small AB = 25\hspace{1mm} cm$ and $\small AC = 7\hspace{1mm} cm$, find BC.

P Pankaj Sanodiya

As we know,

In a Right-angled Triangle: By Pythagoras Theorem,

$(Hypotenus)^2=(Base)^2+(Perpendicular)^2$

As ABC is a right-angled triangle with

Base = AC= 7 cm.

Perpendicular = BC

Hypotenuse = AB = 25 cm

So, By Pythagoras theorem,

$(AB)^2=(AC)^2+(BC)^2$

$(25)^2=(7)^2+(BC)^2$

$(BC)^2=(25)^2-(7)^2$

$(BC)^2=625-49$

$(BC)^2= 576$

$BC= 24$

Hence, Length od BC is 24 cm.

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