# 1.  ABC is an isosceles triangle with $AB=AC$ (Fig 7.17). Take a trace-copy of $\Delta ABC$ and also name it as $\Delta ABC$             (i) State the three pairs of equal parts in $\Delta ABC \; and \: \Delta ACB$.             (ii) Is $\Delta ABC \cong \Delta ACB$? Why or why not?             (iii) Is $\angle B = \angle C$ ? Why or why not?

P Pankaj Sanodiya

Here, in $\Delta ABC \; and \: \Delta ACB$.

i)the three pairs of equal parts in $\Delta ABC \; and \: \Delta ACB$ are

AB = AC

BC = CB

AC = AB

ii)

Hence By SSS Congruency rule, they both are congruent.

$\Delta ABC \cong \Delta ACB$

iii) Yes, $\angle B = \angle C$ because $\Delta ABC \; and \: \Delta ACB$ are congruent and by equating the corresponding parts of the triangles we get,

$\angle B = \angle C$.

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