2.(ii) AD is an altitude of an isosceles triangle ABC in which $\small AB=AC$. Show that   (ii) AD bisects $\small \angle A$.

D Devendra Khairwa

In the previous part of the question we have proved that    $\Delta ABD\ \cong \ \Delta ACD$

Thus by c.p.c.t., we can write :

$\angle BAD\ =\ \angle CAD$

Hence $AD$  bisects  $\angle A$ .

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