# Q 1.10: An electric dipole with dipole moment $4\times 10^{-9} Cm$ is aligned at $30^{\circ}$ with the direction of a uniform electric field of magnitude $5\times 10^{4}NC^{-1}$ . Calculate the magnitude of the torque acting on the dipole.

Given,

Electric dipole moment, p = $4\times 10^{-9} Cm$

$\Theta = 30^{0} \ \therefore sin\Theta = 0.5$

E = $5\times 10^{4}NC^{-1}$

We know , Torque acting on a dipole is given by:

$\tau = p \times E$

$\implies \tau = p Esin\Theta = 4\times10^{-9} \times5\times10^{4}\times0.5 \ Nm$

$\implies \tau =10^{-4}Nm$

Therefore, magnitude of torque acting on the dipole is $10^{-4}Nm$

## Related Chapters

### Preparation Products

##### JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
##### Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
##### Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
##### Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-