Q 1.10: An electric dipole with dipole moment 4\times 10^{-9} Cm is aligned at 30^{\circ} with the direction of a uniform electric field of magnitude 5\times 10^{4}NC^{-1} . Calculate the magnitude of the torque acting on the dipole.

Answers (1)

Given,

Electric dipole moment, p = 4\times 10^{-9} Cm

\Theta = 30^{0} \ \therefore sin\Theta = 0.5

E = 5\times 10^{4}NC^{-1}

We know , Torque acting on a dipole is given by:

\tau = p \times E

\implies \tau = p Esin\Theta = 4\times10^{-9} \times5\times10^{4}\times0.5 \ Nm

\implies \tau =10^{-4}Nm

Therefore, magnitude of torque acting on the dipole is 10^{-4}Nm

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