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- #NCERT
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2.23 An electrical technician requires a capacitance of in a circuit across a potential difference of 1 kV. A large number of
capacitors are available to him each of which can withstand a potential difference of not more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors
Answers (1)
Let's assume n capacitor connected in series and m number of such rows,
Now,
As given
The total voltage of the circuit = 1000V
and the total voltage a capacitor can withstand = 400
From here the total number of the capacitor in series
Since the number of capacitors can never be a fraction, we take n = 3.
Now,
Total capacitance required =
Number of rows we need
Hence Capacitors should be connected in 6 parallel rows where each row contains 3 capacitors in series.
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