An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach minus 350 m.

Answers (2)

Given,

Initial height = 10\ m

Final depth = -350\ m

\therefore Total distance the elevator has to descend = Final position - Initial position

|(-350) - 10| = 360 \ m

Also,

Time the elevator takes to descend 6\ m = 1\ min

\therefore Time the elevator takes to descend 360\ m =

\frac{1}{60}\times360\ min = 60\ min

= 1\ hour

7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.

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