Q7.12  (a) An LC circuit contains a 20mH inductor and a 50\mu F capacitor with an initial charge of 10mC. The resistance of the circuit is negligible. Let the instant the circuit is closed be t=0.

What is the total energy stored initially? Is it conserved during LC oscillations?

Answers (1)

Given,

The inductance of the inductor:

 L=20mH=20*10^{-3}H

The capacitance of the capacitor :

 C=50\mu F=50*10^{-6}F

The initial charge on the capacitor:

Q=10mC=10*10^{-3}C

Total energy present at the initial moment:

E_{initial}=\frac{Q^2}{2C}=\frac{(10*10^{-3})^2}{2*50*10^{-6}}=1J

Hence initial energy in the circuit is 1J. Since we don't have any power-consuming element like  resistance in the circuit, the energy will be conserved

 

 

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