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Q 7.48     Assuming complete dissociation, calculate the pH of the following solutions: 

     (c)      0.002 M HBr 

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$\begin{aligned} & \mathrm{HBr}+\mathrm{H}_2 \mathrm{O} \longleftrightarrow \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{Br}^{-} \\ & {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=[\mathrm{HBr}]} \\ & \begin{aligned} & \Rightarrow {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=.002 } \\ & \begin{aligned} & \mathrm{pH}=-\log \left[\mathrm{H}_3 \mathrm{O}^{+}\right] \\ & \quad=-\log (0.002) \\ & \quad=2.69\end{aligned}\end{aligned}\end{aligned}$

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Satyajeet Kumar

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