Q 7.48 Assuming complete dissociation, calculate the pH of the following solutions:
(c) 0.002 M HBr
$\begin{aligned} & \mathrm{HBr}+\mathrm{H}_2 \mathrm{O} \longleftrightarrow \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{Br}^{-} \\ & {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=[\mathrm{HBr}]} \\ & \begin{aligned} & \Rightarrow {\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=.002 } \\ & \begin{aligned} & \mathrm{pH}=-\log \left[\mathrm{H}_3 \mathrm{O}^{+}\right] \\ & \quad=-\log (0.002) \\ & \quad=2.69\end{aligned}\end{aligned}\end{aligned}$