Go To Your Study Dashboard

3.5 At room temperature (27.0 °C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the material of the resistor is $1.70\times 10^{-4}\degree C^{-1}$ .

Answers (1)

H HARSH KANKARIA

Given,

Temperature coefficient of filament, $\alpha$ = $1.70\times 10^{-4}\degree C^{-1}$

$T_1= 27\degree C$ ; $R_1 = 100 \Omega$

Let $T_2$ be the temperature of element, $R_2= 117\Omega$

(Positive $\alpha$ means that the resistance increases with temperature. Hence we can deduce that $T_2$ will be greater than $T_1$ )

We know,

$R_2 = R_1[1 + \alpha \Delta T]$

$\implies$ $117 = 100[1 +(1.70\times 10^{-4})(T_2 - 27) ]$

$\\ \Rightarrow T_2-27=\frac{117-100}{1.7\times10^{-4}}\\\Rightarrow T_2-27=1000\\\Rightarrow T_2=1027^\circ C$

Hence, the temperature of the element is 1027 °C.

Similar Questions

Latest Asked Questions

Most Viewed Questions

Related Chapters

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 39999/-

Buy Now

Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-

Buy Now

NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-

Buy Now

NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-

Buy Now

NEET Foundation + Knockout NEET 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-

Buy Now

Boost your Preparation for JEE Main with our Foundation Course

Start Now

Exams

Articles

Questions