# 3.3 (b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

Since the resistances are in series, the current through each one of them will be equal to the current through the circuit but voltage/ potential drop will be different.

Total resistance, R = 6 Emf, V = 12 V

According to Ohm's law:

V = IR 12 = I x  6 I = 12/6 = 2 A

Now, Using the same relation, voltage through resistors:

1 : V(1) = 2 x 1 = 2V

2 : V(2) = 2 x 2 = 4V

3 : V(3) = 2 x 3 = 6V

(Note: V(1) + V(2) + V(3) = 2 + 4 + 6 = 12 V )

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