3.4    (b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.

Answers (1)

Since the resistances are in parallel, the voltage across each one of them will be equal.

Emf, V = 20 V

According to Ohm's law:

V = IR \implies I = V/R

Therefore, current across each one of them is:

2\Omega:  I = 20/2 = 10 A

4\Omega:  I = 20/4 = 5 A

5\Omega:  I = 20/5 = 4 A

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