8.24 Calculate the number of unpaired electrons in the following gaseous ions:

(ii)\; Cr^{3+}

Answers (1)
M manish

Electronic configuration of chromium is Cr = 3d^{5}4s^{1}. The number of unpaired electron in Cr^{3+} is 3
Cr^{3+}(Z=24) =\left [ Ar \right ] 3d^{3}
after losing 3 electron, Cr has 3 electron left d-orbital

 

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