Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. Calculate the number of unpaired electrons in the following gaseous ions: Cr^3+
# NCERT

8.24 Calculate the number of unpaired electrons in the following gaseous ions:

(ii)\; Cr^{3+}

Answers (1)
M manish

Electronic configuration of chromium is Cr = 3d^{5}4s^{1}. The number of unpaired electron in Cr^{3+} is 3
Cr^{3+}(Z=24) =\left [ Ar \right ] 3d^{3}
after losing 3 electron, Cr has 3 electron left d-orbital

 

Similar Questions

Related Chapters

Preparation Products

Knockout NEET Sept 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
Buy Now
Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
Buy Now
Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Test Series NEET Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 11999/-
Buy Now
Exams
Articles
Questions