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  • Calculate the number of unpaired electrons in the following gaseous ions: Cr^3+

8.24 Calculate the number of unpaired electrons in the following gaseous ions:

(ii)\; Cr^{3+}

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The electronic configuration of chromium is Cr = 3d^{5}4s^{1}. The number of unpaired electrons in Cr^{3+} is 3
Cr^{3+}(Z=24) =\left [ Ar \right ] 3d^{3} after losing 3 electrons, Cr has 3 electrons left in the d-orbital.

 

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