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Q2. Construct a triangle ABC in which BC = 8cm, \angle B = 45\degree° and AB - AC = 3.5cm

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The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of 45^{\circ} at point B i.e., \angle XBC.


Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.(AB-AC).

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

XCD 45

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

atep 3

Step 5: Join AC, to get the required triangle \triangle ABC.


Posted by

Divya Prakash Singh

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