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# Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB – AC = 3.5 cm.

Q2. Construct a triangle ABC in which $BC = 8cm$, $\angle B = 45\degree$° and $AB - AC = 3.5cm$

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The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of $45^{\circ}$ at point B i.e., $\angle XBC.$

Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.$(AB-AC)$.

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

Step 5: Join AC, to get the required triangle $\triangle ABC.$

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