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  • Construct ∆ABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

Q 1.     Construct \Delta ABC, given m\angle A=60^{\circ}, m\angle B=30^{\circ} and AB = 5.8 cm.

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\Delta ABC, given m\angle A=60^{\circ}, m\angle B=30^{\circ} and AB = 5.8 cm :

1. Draw the line AB=5.8 cm 

2. At A making an angle 60 degrees with AB draw a line AX

3. At B making an angle 30 degrees with AB draw a line BY

4. The lines AX and BY intersect at C ( in case the drawn line AX or BY is small extend it to intersect each other)

ABC is the requires triangle

 

Posted by

Pankaj Sanodiya

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