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1. Determine order and degree (if defined) of differential equation.

   \frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0

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Given function is
\frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0
We can rewrite it as
y^{''''}+\sin(y''') =0
Now, it is clear from the above that, the highest order derivative present in differential equation is  y^{''''}

Therefore, the order of the given differential equation \frac{\mathrm{d} ^4y}{\mathrm{d} x^4} +\sin(y''')=0  is  4
Now, the given differential equation is not a polynomial equation in its derivatives
Therefore, it's a degree is not defined

Posted by

Gautam harsolia

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