8. Determine order and degree (if defined) of differential equation

       y' + y = e^x 

Answers (1)
G Gautam harsolia

Given function is
y' + y = e^x
\Rightarrow y^{'}+y-e^x=0

Now, it is clear from the above that, the highest order derivative present in differential equation is  y^{'}

Therefore, order of given differential equation  y^{'}+y-e^x=0 is  1
Now, the given differential equation is  a polynomial equation in it's dervatives   y^{'} and power raised to y^{'}  is 1
Therefore, it's  degree is 1

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