# 8. Determine order and degree (if defined) of differential equation       $y' + y = e^x$

G Gautam harsolia

Given function is
$y' + y = e^x$
$\Rightarrow$ $y^{'}+y-e^x=0$

Now, it is clear from the above that, the highest order derivative present in differential equation is  $y^{'}$

Therefore, order of given differential equation  $y^{'}+y-e^x=0$ is  1
Now, the given differential equation is  a polynomial equation in it's dervatives   $y^{'}$ and power raised to $y^{'}$  is 1
Therefore, it's  degree is 1

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