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6.Determine order and degree (if defined) of differential equation

    (y''')^2 + (y'')^3 + (y')^4 + y^5= 0

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Given function is
(y''')^2 + (y'')^3 + (y')^4 + y^5= 0
Now, it is clear from the above that, the highest order derivative present in differential equation is  y^{'''}

Therefore, order of given differential equation  (y''')^2 + (y'')^3 + (y')^4 + y^5= 0 is  3
Now, the given differential equation is  a polynomial equation in it's derivatives y^{'''} , y^{''} \ and \ y^{'}   and power raised to y^{'''}  is 2
Therefore, it's  degree is 2

Posted by

Gautam harsolia

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