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Q 1  Differentiate w.r.t. x the function in Exercises 1 to 11.

         ( 3x^2 - 9x + 5 )^9

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Given function is
f(x)=( 3x^2 - 9x + 5 )^9
Now, differentiation w.r.t. x is
f^{'}(x)=\frac{d(f(x))}{dx}=\frac{d((3x^2-9x+5)^9)}{dx}= 9(3x^2-9x+5)^8.(6x-9)
                                                                                    = 27(2x-3)(3x^2-9x+5)^8
Therefore, differentiation w.r.t. x is  27(3x^2-9x+5)^8(2x-3)
 

Posted by

Gautam harsolia

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